c(2-3c)+3(c^2-4)=0

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Solution for c(2-3c)+3(c^2-4)=0 equation: 



c(2-3c)+3(c^2-4)=0

We add all the numbers together, and all the variables

c(-3c+2)+3(c^2-4)=0

We multiply parentheses

-3c^2+3c^2+2c-12=0

We add all the numbers together, and all the variables

2c-12=0

We move all terms containing c to the left, all other terms to the right

2c=12

c=12/2

c=6

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